4.0t^2-27.53t-115=0

Solution for 4.0t^2-27.53t-115=0 equation:

4.0t^2-27.53t-115=0

a = 4.0; b = -27.53; c = -115;
Δ = b2-4ac
Δ = -27.532-4·4.0·(-115)
Δ = 2597.9009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27.53)-\sqrt{2597.9009}}{2*4.0}=\frac{27.53-\sqrt{2597.9009}}{8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27.53)+\sqrt{2597.9009}}{2*4.0}=\frac{27.53+\sqrt{2597.9009}}{8}
$